Re: count of obj

Both queries are using the same access path (full scan+sort+filter), but the 1st one is mathematically incorrect. 1/1/x=x => x/1024/1024/1024=(x*1024)/(1024*1024)=x/1024. That will give all segments > 1KB, which was probably not your intention.

On 03/06/2004 12:18:28 AM, "Kommareddy, Srinivas (MED, Wissen Infotech)" wrote:
> Hi MG,
>
> Thanks for the query.
>
> 1 more...
>
> which is the efficient query to execute on a prod db:
>
>
> select segment_name, round(sum(bytes)/1024/1024/1024) from dba_segments
> group by segment_name
> having round(sum(bytes)/1024/1024/1024) >1;
>
> select segment_name, sum(bytes) from dba_segments
> group by segment_name
> having sum(bytes)>1048576*1024 ;
>
>
> Tx and Regards,
> Srinivas
>
> -----Original Message-----
> From: oracle-l-bounce_at_freelists.org
> [mailto:oracle-l-bounce_at_freelists.org] On Behalf Of Mladen Gogala
> Sent: Saturday, March 06, 2004 10:40 AM
> To: oracle-l_at_freelists.org
> Subject: Re: count of obj
>
> select count(*)
> ( from (select owner,segment_name,segment_type,sum(bytes)
> from dba_extents
> group by owner,segment_name,segment_type
> having sum(bytes)>1048576*1024
> )
> /
>
>
> On 03/05/2004 11:54:38 PM, "Kommareddy, Srinivas (MED, Wissen Infotech)"
> wrote:
> > Hi All,
> >
> > Can somebody give a simple query to find
> >
> > the count(*) of objects which have size >1 Gig
> >
> > its not this.
> >
> > select segment_name, round(sum(bytes)/1024/1024/1024) from
> dba_segmnets
> > group by segment_name
> > having round(sum(bytes)/1024/1024/1024) >1;
> >
> >
> > Need just count(*) of objects in the db > 1Gig size
> >
> > Tx and Regards,
> > Srinivas
> >
>
> --
> Mladen Gogala
> Oracle DBA
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-- 
Mladen Gogala
Oracle DBA
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