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The query proposed by Anthony Hsu assumes that the tablespace has an 8K block size.
Instead use the query below. Of course the result will be in bytes, not gigabytes, but any good DBA can instantly convert bytes to gigabytes or terabytes at a glance. :)
P.S. I include LOB indexes in the table total. Some people might argue that those should be in the index total, not the table total, but I figure that without the LOB column those indexes wouldn't be there so they should properly be counted in the table total.
select sum (x.bytes)
from
(select a.bytes
from dba_segments a
where a.owner = '&&table_owner'
and a.segment_name = '&&table_name' and a.segment_type in ('TABLE', 'TABLE PARTITION', 'TABLE SUBPARTITION')union all
and b.table_name = '&&table_name' and b.column_name = c.column_name and d.owner = c.owner and d.segment_name = c.segment_name and d.segment_type in ('LOBSEGMENT', 'LOB PARTITION', 'LOB SUBPARTITION')union all
and e.table_name = '&&table_name' and e.column_name = f.column_name and g.owner = f.owner and g.segment_name = f.index_name and g.segment_type in ('LOBINDEX', 'INDEX PARTITION', 'INDEX SUBPARTITION')) x ;
-----Original Message-----
Hsu, Anthony C., ,CPMS
Try:
SELECT segment_type, segment_name,BLOCKS*8192/1024 "Kb"
FROM DBA_SEGMENTS WHERE OWNER=UPPER('<owner>') AND SEGMENT_NAME = UPPER('<table_name>');
-----Original Message-----
Could somebody help me in finding the actual size of an oracle table in GB.
-- Please see the official ORACLE-L FAQ: http://www.orafaq.net -- Author: Jacques Kilchoer INET: Jacques.Kilchoer_at_quest.com Fat City Network Services -- 858-538-5051 http://www.fatcity.com San Diego, California -- Mailing list and web hosting services --------------------------------------------------------------------- To REMOVE yourself from this mailing list, send an E-Mail message to: ListGuru_at_fatcity.com (note EXACT spelling of 'ListGuru') and in the message BODY, include a line containing: UNSUB ORACLE-LReceived on Wed Oct 15 2003 - 15:24:25 CDT
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