Dan (and Charlie),
Thanks.
Good suggestions, but the IN clause contains just
over 1700 values.
Puzzling, huh?
steve
- "Fink, Dan" <Dan.Fink_at_mdx.com> wrote:
> It is a little awkward, but a union in an
> inline query may do the trick:
>
> 1 select a.code
> 2 from (select '10' code from dual union
> 3 select '20' code from dual union
> 4 select '30' code from dual union
> 5 select '40' code from dual union
> 6 select '50' code from dual ) a
> 7* where a.code not in (select
> to_char(deptno) from emp)
> SQL> /
>
> CO
> --
> 40
> 50
>
> Dan Fink
>
> -----Original Message-----
> From: Steven Haas [mailto:steven.haas_at_snet.net]
> Sent: Monday, September 23, 2002 10:28 AM
> To: Multiple recipients of list ORACLE-L
> Subject: SQL question
>
>
> Good morning list,
>
> Environment HP-UX 11.0 Oracle 8.1.6
>
> Can anyone help with this SQL.
>
> I can get a result set of values from a table
> that match a given list of values -
>
> select code
> from table
> where code in ('A','B','C','D','E')
>
> I can get a result set of values from a table
> that do not match a given list of values -
>
> select code
> from table
> where code not in ('A','B','C','D','E')
>
> So far so good.
>
> Now, how do I get the set of values from the
> list
> that do NOT have a matching value in the table?
>
> I cannot create any objects in the schema I am
> working in otherwise I would create a table
> with
> the values and do a minus, but I can't figure
> out
> how to do it in SQL only.
>
> Thanks in advance, folks.
>
> Steve
> --
> Please see the official ORACLE-L FAQ:
> http://www.orafaq.com
> --
> Author: Steven Haas
> INET: steven.haas_at_snet.net
>
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Received on Mon Sep 23 2002 - 12:38:28 CDT