Re: SQL Query

From: sundeep maini <sundeep_maini_at_yahoo.com>
Date: Thu, 25 Sep 2003 14:14:51 -0800
Message-ID: <F001.005D1153.20030925141451@fatcity.com>

Mike,

Just wanted to supplement your example with another one from my environment (uses nested tables with CAST and MULTISET to achieve the same):

SELECT c.customer_id

      ,customer_name
      ,utils.code_table_to_string(CAST( MULTISET(
        SELECT distinct dlr_dealer_code
          FROM dealer_customers dc
		       ,dlr_dealer_master_t
         WHERE dc.customer_id = dc_in.customer_id
		   AND dlr_dealer_id = dc.dealer_id
		 ORDER BY dlr_dealer_code
		) AS code_table_t
	  )) spans_these_dealers
 FROM customers c
     ,(
       SELECT customer_id
	     FROM dealer_customers 
		GROUP BY customer_id
		HAVING COUNT(distinct dealer_id) > 1
	  ) dc_in

WHERE dc_in.customer_id = c.customer_id;

Does eseentially the same thing. In this case it concatenates the dealer_codes per customer (identifies customers spanning multiple dealers) on the same row. Here is a sample of the output:

2969473096	Mountain Enterprises Inc	D100,D470,D480
2969473121	K C Construction	        B010,B150,B190
2969473195	GOODFELLOW BROS	                H140,H330

The TYPE code_table_t is defined as:
TYPE CODE_TABLE_T IS table of varchar2(3000);

And the conversion function is very similar in its functionality to dbms_utility.comma_to_table procedure:

FUNCTION code_table_to_string (in_table code_table_t, in_rec_sep varchar2 DEFAULT config.c_rec_sep)

   RETURN delimited_list_t
 IS
   v_list delimited_list_t;
 BEGIN
   FOR i IN 1..in_table.COUNT
   LOOP

     IF i = 1
	 THEN
	   v_list := in_table(1);
	 ELSE
       v_list := v_list||in_rec_sep||in_table(i);
	 END IF;

   END LOOP;
   RETURN v_list;
 END code_table_to_string;

As opposed your suggestion of using the following:

SELECT id, CONCAT_LIST(CURSOR(
> SELECT text
> FROM mike m_in

       ORDER BY ordr


>      WHERE m_in.id = m.id)) list

> FROM ( select distinct id from mike) m; --- Mike Spalinger <Michael.Spalinger_at_Sun.COM> wrote:

> Imran,
> 
> Tom Kyte has a thread that might help:
>

http://asktom.oracle.com/pls/ask/f?p=4950:8:1554835115460038644::NO::F4950_P8_DISPLAYID,F4950_P8_CRITERIA:229614022562,

> 
> Essentially, you can do this:
> 
> CREATE or replace FUNCTION CONCAT_LIST( cur SYS_REFCURSOR )
>    RETURN  VARCHAR2 IS


>      ret VARCHAR2(32000);

>      tmp VARCHAR2(4000);

> BEGIN


>      loop

>          fetch cur into tmp;

>          exit when cur%NOTFOUND;

>              ret := ret || ' ' || tmp;

>      end loop;

>      RETURN ret;

> END;
> /
> 
> SQL> select * from mike;
> 


>          ID TEXT             ORDR

> ---------- ---------- ----------


>           1 B                   2

>           1 A                   1

>           1 C                   3

> 
> SELECT id, SUBSTR(CONCAT_LIST(CURSOR(


>     SELECT text

>        FROM (select id, text, ordr from mike order by ordr) ee

>        WHERE e.id = ee.id)),1,40) list

> FROM ( select distinct id from mike) e;
> 


>          ID LIST

> ---------- --------------------


>           1  A B C

> 
> Mike
> 
> 
> Imran Ashraf wrote:
> > Hi,
> > 
> > I have the following data , table Temp
> > 
> > ID  Text   Order
> > 1     B        2
> > 1     A        1
> > 1     C        3
> > 
> > 
> > I want to write a query which says: wherever there is more than 1
> occurrence
> > of ID then  concatenate the text in the order specified in the
> order column.
> > So i would get:
> > 
> > ID  Text
> > 1     A B C
> > 
> > Any suggestions?
> > 
> > Thanks
> > 
> > Imran
> 
> 
> -- 
> Please see the official ORACLE-L FAQ: http://www.orafaq.net
> -- 
> Author: Mike Spalinger
>   INET: Michael.Spalinger_at_Sun.COM
> 
> Fat City Network Services    -- 858-538-5051 http://www.fatcity.com
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=====

Sundeep Maini 
Consultant 
Currently on Assignement at Caterpillar Peoria
sundeep_maini_k_at_cat.com 

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-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.net
-- 
Author: sundeep maini
  INET: sundeep_maini_at_yahoo.com

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Received on Thu Sep 25 2003 - 17:14:51 CDT