RE: Query help !!!

From: Nicoll, Iain (Calanais) <iain.nicoll_at_calanais.com>
Date: Fri, 22 Jun 2001 10:45:02 -0700
Message-ID: <F001.003340A0.20010622105247@fatcity.com>

Leslie,

The query below will find all those with any number of 'F's and at least one status that is not 'F'.

select distinct customer_id
from mytablename t
where status = 'F'
and exists (select ''

              from mytablename t2
              where t2.customer_id = t.customer_id
              and   t2.status     != 'F')

Cheers

Iain Nicoll
-----Original Message-----
Sent: 22 June 2001 19:06
To: Multiple recipients of list ORACLE-L

Just to clearfy my previous question (as follow):

if 1 has F and A and B, that what I want.

If 1 has F all the time, that's not what I want. If 1 has A, B, C, but never F, that's not what I want either.

• Leslie Lu <leslie_y_lu_at_yahoo.com> wrote:
  > Hi,
  >
  > If I have this:
  > Customer_id Status
  > ---------- -----------
  > 1 F
  > 1 A
  > 1 B
  > 2 F
  > 2 F
  > 3 A
  > 3 B
  >
  > How do I found out a customer who has both F and not
  > F
  > for them. (If he only gets F, or gets other than F,
  > that's fine). In this case, I should get 1. Thank
  > you! I need this badly!
  >
  > __________________________________________________
  > Do You Yahoo!?
  > Get personalized email addresses from Yahoo! Mail
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  ---

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-- 
Author: Leslie Lu
  INET: leslie_y_lu_at_yahoo.com

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-- 
Author: Nicoll, Iain (Calanais)
  INET: iain.nicoll_at_calanais.com

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Received on Fri Jun 22 2001 - 12:45:02 CDT