Re: Query help !!!

Here is one way:

select distinct customer_id c1 where exists (select 'X' from customer_id where customer_id = c1.customer_id and status = 'F')
and exists
(select 'X' from customer_id where customer_id = c1.customer_id and status <> 'F')

At 10:05 AM 6/22/01 -0800, you wrote:
>Just to clearfy my previous question (as follow):
>
>if 1 has F and A and B, that what I want.
>
>If 1 has F all the time, that's not what I want.
>If 1 has A, B, C, but never F, that's not what I want
>either.
>
>--- Leslie Lu <leslie_y_lu_at_yahoo.com> wrote:
> > Hi,
> >
> > If I have this:
> > Customer_id Status
> > ---------- -----------
> > 1 F
> > 1 A
> > 1 B
> > 2 F
> > 2 F
> > 3 A
> > 3 B
> >
> > How do I found out a customer who has both F and not
> > F
> > for them. (If he only gets F, or gets other than F,
> > that's fine). In this case, I should get 1. Thank
> > you! I need this badly!
> >
> > __________________________________________________
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>
>
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