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Hi ,
Thank you very much for your help.
Based on the article ,
the system has 8 cpus .
5551 secs ( 92) min cpu time in 60 minutes : if i have 2 cpus utilized
100 % then , i can get 120 min. cpu time , here only 92 min. cpu time
can be achieved by using only 2 cpus, i have 8 , so only %20 of total
cpu resources is used.
Is it correct?
The application is an oltp which has strict transaction limitations such as every business procedure has 4 secs. time out value.
This is another part of the report , which shows high numbers of av rd(ms)
Tablespace Filename
Av Av Av Av Buffer Av Buf Reads Reads/s Rd(ms) Blks/Rd Writes Writes/s WaitsWt(ms)
UNDO_TBS_FIRST /dev/vx/rdsk/datadg/UNDOFIRST 1 0 110.0 1.0 1,021 0 3 0.0 /dev/vx/rdsk/datadg/verde_raw_undo12_8g 1 0 90.0 1.0 2,555 1 17 0.0 /dev/vx/rdsk/datadg/verde_raw_undo1_1g 1 0 90.0 1.0 850 0 61.7
UNDO_TBS_SECOND /dev/vx/rdsk/datadg/UNDOSECOND 1 0 90.0 1.0 1 0 0 /dev/vx/rdsk/datadg/verde_raw_undo22_1g 1 0 120.0 1.0 1 0 2 0.0 /dev/vx/rdsk/datadg/verde_raw_undo2_1g 1 0 90.0 1.0 1 0 0
Kind Regards,
hope
joel garry wrote:
> hopehope_123 wrote:
> > Hi Gurus ,
> >
> >
> > Snap Id Snap Time Sessions Curs/Sess Comment
> > --------- ------------------ -------- ---------
> > -------------------
> > Begin Snap: 2428 07-Dec-06 16:10:00 96 12.2
> > End Snap: 2429 07-Dec-06 17:10:00 167 14.4
> > Elapsed: 60.00 (mins)
> >
> >
> > Top 5 Timed Events
> > ~~~~~~~~~~~~~~~~~~
> > % Total
> > Event Waits Time (s)
> > Ela Time
> > -------------------------------------------- ------------ -----------
> > --------
> > CPU time 5,551
> > 69.62
> > db file sequential read 37,573 689
> > 8.65
> > log file parallel write 76,392 406
> > 5.10
> > log file sync 19,417 377
> > 4.72
> > db file scattered read 16,016 239
> > 2.99
> >
> >
> > This is a 60min. interval output of statspack. It says 5551 second is
> > spent on cpu. 5551 sec. is greater than 60min. What does this value
> > mean? How can i comment about ?Is it worth the effort to deal with the
> > cpu time ?
>
>