Re: Time stamp diff function
Date: Fri, 7 Nov 2014 13:32:33 -0600
Message-Id: <AAB96347-B39D-40D0-8944-529C4F251EFB_at_gmail.com>
I do admit that I am surprised Oracle doesn't include an embedded function to do this. I would think its a pretty common need.
Sent from my iPad
> On Nov 7, 2014, at 11:58 AM, Kim Berg Hansen <kibeha_at_gmail.com> wrote:
>
> Hi again, Andrew
>
> Sorry, my previous take on the function had a mistake.
> Since I divide first and then multiply, rounding errors could occur.
> For example an interval of 1 hour and 15 minutes would become 75.0000000000000001 minutes.
>
> Here's a better version:
>
> create or replace function tsdiff(ts1 in timestamp, ts2 in timestamp, units in varchar2)
> /* units - l=millisecond s=second, m=minute, h=hour, d=day */
> return number
> is
> diff interval day(9) to second(9) := ts1 - ts2;
> begin
> return (
> extract(day from diff)*24*60*60
> + extract(hour from diff)*60*60
> + extract(minute from diff)*60
> + extract(second from diff)
> ) / case (lower(units))
> when 'l' then 1/1000
> when 's' then 1
> when 'm' then 60
> when 'h' then 60*60
> when 'd' then 24*60*60
> else null
> end;
> end;
> /
>
>
>
> Regards
>
>
> Kim Berg Hansen
>
> http://dspsd.blogspot.com
> kibeha_at_gmail.com
> _at_kibeha
>
>
>
>> On Fri, Nov 7, 2014 at 6:09 PM, Kim Berg Hansen <kibeha_at_gmail.com> wrote: >> Hi, Andres >> >> We have NUMTODSINTERVAL, but not DSINTERVALTONUM, sadly. >> So a function like you make is probably needed, I think. >> >> A couple small things I can think of: >> 1) There's a lot of repetition of code. >> 2) Why select from dual? >> >> Point 1 makes not much difference performance wise. >> Point 2 makes unnecessary context switches between SQL and PL/SQL and can make a bit of performance difference. >> >> My take on a rewrite would be: >> >> create or replace function tsdiff(ts1 in timestamp, ts2 in timestamp, units in varchar2) >> /* units - l=millisecond s=second, m=minute, h=hour, d=day */ >> return number >> is >> diff interval day(9) to second(9) := ts1 - ts2; >> begin >> return ( >> extract(day from diff) >> + extract(hour from diff)/24 >> + extract(minute from diff)/24/60 >> + extract(second from diff)/24/60/60 >> ) * case (lower(units)) >> when 'l' then 24*60*60*1000 >> when 's' then 24*60*60 >> when 'm' then 24*60 >> when 'h' then 24 >> when 'd' then 1 >> else null >> end; >> end; >> / >> >> There can be other rewrites that also would be fine, but this works on an 11.2 instance (at least with a few tests I made :-) >> >> I am not quite sure - but perhaps the select from dual trick might be necessary on old versions, as PL/SQL didn't always have all SQL functions - maybe EXTRACT used to only SQL? I am not stating that for certain, but maybe... >> >> >> >> Regards >> >> >> Kim Berg Hansen >> >> http://dspsd.blogspot.com >> kibeha_at_gmail.com >> _at_kibeha >> >> >> >> >> >>> On Fri, Nov 7, 2014 at 3:41 PM, Andrew Kerber <andrew.kerber_at_gmail.com> wrote: >>> I don't typically work with time intervals a lot, so I am not really familiar with getting a difference between timestamps. I wrote the function below to subtract two timestamps. Does anyone have a better example of how to do this: >>> >>> create or replace function tsdiff(ts1 in timestamp, ts2 in timestamp, units in varchar2) >>> /* units - l=millisecond s=second, m=minute, h=hour, d=day */ >>> return number >>> is >>> diffval number; >>> unitsin char(1); >>> begin >>> unitsin:=lower(units); >>> if unitsin='l' >>> then >>> select >>> extract(day from (ts1-ts2))*24*60*60*1000 >>> + extract(hour from (ts1-ts2))*60*60*1000 >>> + extract(minute from (ts1-ts2))*60*1000 >>> + extract(second from (ts1-ts2))*1000 >>> into diffval >>> from dual; >>> elsif unitsin='s' >>> then >>> select >>> extract(day from (ts1-ts2))*24*60*60 >>> + extract(hour from (ts1-ts2))*60*60 >>> + extract(minute from (ts1-ts2))*60 >>> + extract(second from (ts1-ts2)) >>> into diffval >>> from dual; >>> elsif unitsin='m' >>> then >>> select >>> extract(day from (ts1-ts2))*24*60 >>> + extract(hour from (ts1-ts2))*60 >>> + extract(minute from (ts1-ts2)) >>> + extract(second from (ts1-ts2))/60 >>> into diffval >>> from dual; >>> elsif unitsin='h' >>> then >>> select >>> extract(day from (ts1-ts2))*24 >>> + extract(hour from (ts1-ts2)) >>> + extract(minute from (ts1-ts2))/60 >>> + extract(second from (ts1-ts2))/60/60 >>> into diffval >>> from dual; >>> elsif unitsin='d' >>> then >>> select >>> extract(day from (ts1-ts2)) >>> + extract(hour from (ts1-ts2))/24 >>> + extract(minute from (ts1-ts2))/24/60 >>> + extract(second from (ts1-ts2))/24/60/60 >>> into diffval >>> from dual; >>> end if; >>> return diffval; >>> end; >>> >>> Sent from my iPad-- >>> http://www.freelists.org/webpage/oracle-l
>
-- http://www.freelists.org/webpage/oracle-lReceived on Fri Nov 07 2014 - 20:32:33 CET