dbms_xplan.display_cursor STARTS, E-ROWS, A-ROWS question on partitioned table with gather_plan_statistics hint
From: <Christopher.Taylor2_at_parallon.net>
Date: Mon, 10 Sep 2012 10:51:59 -0500
Message-ID: <F05D8DF1FB25F44085DB74CB916678E8851576282C_at_NADCWPMSGCMS10.hca.corpad.net>
Is there any special consideration when looking at Starts,E-Rows and A-Rows for Partitioned Tables when using dbms_xplan? In the example below, there is an organization table that returns 17 organizations, for each organization, access this partitioned table.
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Date: Mon, 10 Sep 2012 10:51:59 -0500
Message-ID: <F05D8DF1FB25F44085DB74CB916678E8851576282C_at_NADCWPMSGCMS10.hca.corpad.net>
Is there any special consideration when looking at Starts,E-Rows and A-Rows for Partitioned Tables when using dbms_xplan? In the example below, there is an organization table that returns 17 organizations, for each organization, access this partitioned table.
This partitioned table has 0 sub partitions so it is only partitioned on organization ids - no subsequent subpartitions [yet].
Is Oracle telling me that it actually received 405K rows but only expected 731 rows (17 starts * 43 rows)?
Could this be indicative of gathering statistics incorrectly for partitioned tables? I saw that David Kurtz had a presentation on gathering statistics for partitioned tables but I think his example went into subpartitions.
What considerations should I be considering here (other than just flat out re-gathering statistics)?
| Id | Operation | Name | Starts | E-Rows |E-Bytes| Cost (%CPU)| E-Time | Pstart| Pstop | A-Rows | A-Time | -----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
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| 33 | PARTITION LIST ITERATOR| | 17 | 43 | 4257 | 128 (2)| 00:00:02 | KEY | KEY | 405K|00:00:02.85 | |* 34 | TABLE ACCESS FULL | MON_ACCOUNT | 17 | 43 | 4257 | 128 (2)| 00:00:02 | KEY | KEY | 405K|00:00:02.44 |
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(Again this goes back to my partitioning newbieness)
Chris
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