conditional 'order by'
From: Eugene Pipko <eugene.pipko_at_unionbay.com>
Date: Fri, 19 Dec 2008 08:57:12 -0800
Message-ID: <34DB87F47199374280ADFD2968CDBCFA87D4CF4435@MAIL01KT.seattlepacificindustries.com>
Date: Fri, 19 Dec 2008 08:57:12 -0800
Message-ID: <34DB87F47199374280ADFD2968CDBCFA87D4CF4435@MAIL01KT.seattlepacificindustries.com>
Hi all,
I have a query that needs to be ordered by based on the second letter of the code passed in it.
For instance if the code is '9F9Q' then I'd order by 'F' , then by 'H', then by any other.
If the code is '7H7Q' then I'd order by 'H', then by 'F', then by any other.
I know that I can do it in 2 steps, but is it possible to do in one sql statement?
Select ... From ... Where .... If substr(code,2,1)='F' then Order by decode(code,'F',0,'H',1,2); Elsif substr(code,2,1)='H' then Order by decode(code,'H',0,'F',1,2);End if;
Thanks,
Eugene
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-- http://www.freelists.org/webpage/oracle-lReceived on Fri Dec 19 2008 - 10:57:12 CST