Re: String Manipulation

From: Carel-Jan Engel <cjpengel.dbalert_at_xs4all.nl>
Date: Fri, 18 May 2007 09:35:04 +0200
Message-Id: <1179473704.9951.16.camel@lagavulin.dbalert.eu>

If the first occurrence of the delimiter is the position you want to go to, take any character that is not the delimiter:

• For a delimiter '.', we want any not-dot: ^.
• We want that as many times as possible: [^.]*

  1* select regexp_substr('test1@#!$%.test2.com', '[^.]*') from dual dbalert199.D10B.1.FOTDBA SQL> /
REGEXP_SUB

---

test1@#!$%

HTH Best regards,

Carel-Jan Engel

===
If you think education is expensive, try ignorance. (Derek Bok) ===

On Thu, 2007-05-17 at 16:34 -0700, Jared Still wrote:

>
>
> On 5/17/07, Jeremiah Wilton <jeremiah_at_ora-600.net> wrote:
>
> A regex returning the first word from the address should do
> it:
>
> SQL> select regexp_substr('foo.bar.baz','\w*') from dual;
>
>
>
>
> 16:32:27 SQL>l
> 1* select regexp_substr(' foo-1.bar.baz','[a-z|A-Z|0-9|-]*') from
> dual
> 16:32:28 SQL>/
>
> REGEX
> -----
> foo-1
>
> 1 row selected.
>
> There's probably a metacharacter to shorten that regex, but I can't
> remember and too lazy to look.
>
> --
> Jared Still
> Certifiable Oracle DBA and Part Time Perl Evangelist

--
http://www.freelists.org/webpage/oracle-l

Received on Fri May 18 2007 - 02:35:04 CDT