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Home -> Community -> Mailing Lists -> Oracle-L -> Re: "Merge into" wierdness - solved
Well, I've made some progress on this...
The source table had duplicate records in it based on the key structure mentioned in the ON clause. Once those duplicate records were removed, the statement worked.
Didn't help that the error message was completely wrong! Hope this helps someone from losing a day's work...
-----Original Message-----
From: david wendelken <davewendelken_at_earthlink.net>
Sent: Dec 10, 2004 12:25 PM
To: Oracle-L_at_freelists.org
Subject: "Merge into" wierdness
I'm doing a merge into command where I query a table that holds multiple scenario items in it.
The objective is to transfer the selected scenario items from the "source scenario" to the "destination scenario". Some of those records might have been transferred before, in which case the non-key values are to be updated from the source. If they haven't been transferred before, they get inserted.
The statement worked like a charm.
Then I needed to add another column to the table, and that column needed to be added to the ON clause. I added it and the statement fails - the error message says the column doesn't exist in the table.
"Oracle Error Code = 904
ORA-00904: "L_TO"."UNITTYPEID": invalid identifier "
If I remove the column name from the ON clause, the statement runs.
I'm flat-out certain I didn't mis-spell the column name or its prefix. (I cut-and-pasted the column name from the source select statement and the prefix from other destination columns, plus I've had another set of eyes double-check.) (You would make be very happy if I'm wrong...)
The source select statement in the merge command can clearly find the column, so it's not like I'm pointing to the wrong version of the table or something...
I've got 7 phrases in the ON clause, if that makes a difference.
Any clues? I don't have access to meta-link where I'm at.
Oracle9i Enterprise Edition Release 9.2.0.5.0 - Production With the Partitioning, OLAP and Oracle Data Mining options JServer Release 9.2.0.5.0 - Production
Here's the table and statement, somewhat simplified. Hopefully it will remain readable.
DESCR laydown
Name Null? Type ------------------------------- -------- ---- LAYDOWNID NOT NULL NUMBER(10) ANALYSISVERSIONID NOT NULL NUMBER(10) SCENARIOID NOT NULL NUMBER(10) PAIID NOT NULL NUMBER(10) ORGID NOT NULL NUMBER(10) STATUSCODEID NOT NULL NUMBER(10) ACTIVITYID NOT NULL NUMBER(10) QTY NUMBER(6) ACTIVITYREMARK VARCHAR2(100) ORGIDFROM NUMBER(10) UNITTYPEID NOT NULL NUMBER(10)
MERGE INTO laydown l_to
USING
(SELECT l_src_start.*,l_over_under.qty_over_under
FROM laydown l_src_start
,(SELECT l_ou_temp.activityid, l_ou_temp.paiid ,l_ou_temp.orgid, l_ou_temp.unittypeid ,SUM(l_ou_temp.qty) qty_over_under FROM ( SELECT l_ou.activityid ,l_ou.paiid
,l_ou.orgidfrom orgid ,l_ou.unittypeid
,l_ou.qty * -1 qty
FROM laydown l_ou WHERE l_ou.analysisversionid = 1 AND l_ou.scenarioid = 3 AND l_ou.orgidfrom IS NOT NULL UNION ALL SELECT l_ou.activityid ,l_ou.paiid
,l_ou.orgid ,l_ou.unittypeid
,l_ou.qty
FROM laydown l_ou WHERE l_ou.analysisversionid = 1 AND l_ou.laydownid IN (247) ) l_ou_temp GROUP BY 1,2,3,4 ) l_over_under
AND l_src_start.analysisversionid = 1 AND l_src_start.activityid = l_over_under.activityid (+) AND l_src_start.paiid = l_over_under.paiid (+) AND l_src_start.orgid = l_over_under.orgid (+) AND l_src_start.unittypeid = l_over_under.unittypeid (+) ) l_src ON ( l_src.activityid = l_to.activityid AND l_src.paiid = l_to.paiid AND l_to.orgid = 16 AND l_to.scenarioid = 3 AND l_to.analysisversionid = 1 AND l_to.orgidfrom = l_src.orgid /* barfs on the next line */ AND l_to.unittypeid = l_src.unittypeid)
-- http://www.freelists.org/webpage/oracle-l -- http://www.freelists.org/webpage/oracle-lReceived on Fri Dec 10 2004 - 15:01:41 CST
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