RE: Slow running Query.

From: Juan Carlos Reyes Pacheco <jreyes_at_dazasoftware.com>
Date: Tue, 22 Jun 2004 13:21:24 -0400
Message-Id: <40D86A94.000003.02400@CACHITOSS>

Hi Lex, why you say that, could you showme why please

I show you why I say is the same:
SQL> select * from test;

TEST

Transcurrido: 00:00:00.00
SQL> select count(*) from test where test is null;

COUNT(*)

Transcurrido: 00:00:00.00
SQL> select sum(nvl(test,0)) from test;

SUM(NVL(TEST,0))

Transcurrido: 00:00:00.00
SQL> select nvl(sum(test),0) from test;

NVL(SUM(TEST),0)

Transcurrido: 00:00:00.00

-------Original Message-------

From: oracle-l_at_freelists.org
Date: 06/22/04 12:43:39
To: oracle-l_at_freelists.org
Subject: RE: Slow running Query.

Juan,

unfortunately sum(nvl(column,0)) is not equivalent to nvl(sum(column),0)..

Kind regards,
Lex.

visit my website at http://www.naturaljoin.nl

-----Original Message-----

From: oracle-l-bounce_at_freelists.org
[mailto:oracle-l-bounce_at_freelists.org]On Behalf Of Juan Carlos Reyes Pacheco
Sent: Tuesday, June 22, 2004 17:15
To: oracle-l_at_freelists.org
Subject: RE: Slow running Query.

Hi, I will do t he following

Try creating function indexes on composed columns you are queryin and tellme if this improves something
For example you are using as_date in the where column, but you don't have a index on substr(ca_date,1,4,....

Only to avoid unncesary plsql work
1. instead sum(nvl(column,0)) I'll use nvl(sum(column),0 2. instead of decode use case

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Received on Tue Jun 22 2004 - 12:22:39 CDT