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Home -> Community -> Mailing Lists -> Oracle-L -> RE: update year in date column
There is a minor issue with this approach though. It broke a test case. Look at the last row, since 2000 is a leap year, but 1900 is not a leap year this might not work universally. Barbara does not want to change the date, just the year. Agreed, it will work for Barbara's test case if the rows are only have a value of 2099.
select crdate, add_months(crdate, -1200) from mytabdate
RSHAMSUD_at_OAKSTAGE:ent4pdb1r> /
CRDATE ADD_MONTHS(CRDATE,-1
-------------------- -------------------- 16-SEP-2099 00:00:00 16-SEP-1999 00:00:00 08-OCT-2099 00:00:00 08-OCT-1999 00:00:0028-FEB-2099 00:00:00 28-FEB-1999 00:00:00 29-FEB-2000 00:00:00 28-FEB-1900 00:00:00 Thanks
-----Original Message-----
From: oracle-l-bounce_at_freelists.org
[mailto:oracle-l-bounce_at_freelists.org] On Behalf Of Khedr, Waleed
Sent: Tuesday, March 23, 2004 3:12 PM
To: oracle-l_at_freelists.org
Subject: RE: update year in date column
It's 100 years equals 1200 months.
Use add_month(<column>, -1200)
Waleed
-----Original Message-----
From: Barbara Baker [mailto:barbarabbaker_at_yahoo.com]
Sent: Tuesday, March 23, 2004 3:01 PM
To: oracle-l_at_freelists.org
Subject: update year in date column
OK, I'm just going to bite the bullet and claim total
ignorance here and see if someone takes pity on me :(
(sad face a nice touch, eh?)
Someone has accidently updated 378 records in the customer table. The date changed from 1999 to 2099. I need to change just the year back to 1999 for these records. (I'd like to keep the time stamp, if possible. The month and day are correct.) I looked on metalink, google, and asktom. Some nice examples, but not what I really need.
Thought I'd be clever and subtract 1000 from the date. This works, but I don't know how to get it formatted back into a date.
I'd prefer just sqlplus, but will use pl/sql if necessary.
Here's what I've done so far:
(solaris 9 oracle 9.2.0.4)
JServer Release 9.2.0.4.0 - Production
DOC> CUSNO CUSNAME CRDATE
DOC>---------- ----------------------------------- ---------- DOC> 798489 GILBERT, ROSS 09/16/2099 DOC> 826744 HOEFLER, MATT 10/08/2099 DOC> 795126 FORT, JOETTA09/08/2099
SQL> ---update advdb.custtest_barb SQL> ---set crdate= to_char(crdate,'MM/DD/YYYY')) SQL> ---from customer where cusno=798489; SQL> SQL> select to_date(to_char(crdate,'ddmmyyyy')-1000),'MM/DD/YYYY') 2 from customer where cusno=798489;select
*
SQL> SQL> SQL> --- these both work SQL> select to_char(crdate,'ddmmyyyy') fromcusttest_barb where cusno=798489;
TO_CHAR(
SQL> select to_char(crdate,'ddmmyyyy') - 1000 from custtest_barb where cusno=798489;
TO_CHAR(CRDATE,'DDMMYYYY')-1000
16091099
Thank for any assistance.
Barb
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