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Hello everyone,=20
I can understand why this stmt below doesn't work (invalid table name). Failure happens in the prepare statement. It also doesn't like EXECUTE IMMEDIATE.=20 Can anyone suggest a way around this without hardcoding the table name?=20
$sql_stmt =3D qq{ SELECT count(*)
FROM ? WHERE julian_Run_date =3D ? };
Thank you for any suggestions, comments or website links. =20
Lisa Koivu
Data Janitor with No Mop
Orlando, FL, USA
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