RE: Silly SQL Question

Just a guess:

select distinct
  usr
from
  xxx
where
 (select

    count(*)
  from
    xxx
  group by Usr)
  =
 (select

    count(*)
    from
      xxx
    group by Usr, val)

-----Original Message-----
Sent: Thursday, November 13, 2003 3:29 PM To: Multiple recipients of list ORACLE-L

Gabriel Aragon wrote:
>
> I have a table with like this:
>
> Usr val
> ----------
> GAP 1
> GAP 5
> GAP 7
> JKL 8
> JKL 5
>
> I need a query that returns the user (GAP o JKL) that
> has ALL the values in a list. Example: Having the
> list: 1,5,7 the result will be GAP, but with the
> values 1,5 or 1,5,7,8 there will be no result.
>
> select distinct usr
> from xxx
> where val = All (1,3,5)
>
> I was trying the ALL operator but it works with part
> of the list, I need the user that has (exactly) all
> the values in the list. Any idea?
>
> Maybe it's a simple solution, but after several hours
> I feel blocked.
>
> TIA
> Gabriel
>

select usr
from XXX
where val in (list)
group by usr
having count(*) = number of values in list

does it but assumes that (usr, val) is unique (which can be easily worked-around :
select usr
from (select distinct usr, val

      from XXX)
group by ... )

and also that you know both the list and the number of items in the list, which looks reasonable.
If your intent is to build the queries and the list dynamically, I'd rather suggest storing the list into a temporary table.

-- 
Regards,

Stephane Faroult
Oriole Software
-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.net
-- 
Author: Stephane Faroult
  INET: sfaroult_at_oriole.com

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