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Try:
SELECT segment_type, segment_name,BLOCKS*8192/1024 "Kb"
FROM DBA_SEGMENTS WHERE OWNER=UPPER('<owner>') AND SEGMENT_NAME =UPPER('<table_name>');
Tony
-----Original Message-----
Sent: Wednesday, October 15, 2003 3:24 PM
To: Multiple recipients of list ORACLE-L
Hi All,
Could somebody help me in finding the actual size of an oracle table in GB.
TIA,
Rajesh
--
Please see the official ORACLE-L FAQ: http://www.orafaq.net
--
Author: Hsu, Anthony C., ,CPMS
INET: anthony.hsu_at_cpms.osd.mil
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