SELECT DISTINCT testid
, FIRST_VALUE(name) OVER (PARTITION BY testid ORDER BY ROWID) name
, FIRST_VALUE(status) OVER (PARTITION BY testid ORDER BY ROWID) status
FROM testing
/
--
Vladimir Begun
The statements and opinions expressed here are my own and
do not necessarily represent those of Oracle Corporation.
elain he wrote:
> Hi,
> Could someone shed some light on this.
>
> I'm trying to formulate a query to return distinct value on a column -
> testid.
>
> select * from testing;
> TESTID NAME STATUS
> ---------- -------------------- -----------
> 1 MIKE Y
> 1 JOE Y
> 1 JIM Y
> 2 AMY Y
>
> The output I'm expecting is
> TESTID NAME STATUS
> ---------- -------------------- -----------
> 1 MIKE Y
> 2 AMY Y
>
>
> The query should display the first occurence of the testid and ignore
> records with the same testid.
--
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--
Author: Vladimir Begun
INET: Vladimir.Begun_at_oracle.com
Fat City Network Services -- 858-538-5051 http://www.fatcity.com
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Received on Tue Sep 23 2003 - 16:14:39 CDT
