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Home -> Community -> Mailing Lists -> Oracle-L -> CASE in PL/SQL
Hello ALL,
I am trying to find quarter number from a given date . Here is the description
Our Financial year runs from July thru June. So, Given any date between these dates I need to find 3 quarters(9 months) from it.
July -Sep -> 1st Quarter Oct -Dec -> 2nd Quarter Jan -Mar -> 3rd Quarter Apr -Jun -> 4th Quarter
I got this done using the following Select
select decode(to_char(add_months(sysdate,9),'Q'),
'1','3',
'2','4',
'3','1',
'4','2',
'') Decode function is used to change calender quarter to our Quarter.
But I am unable to find the Year for that quarter. I was using Case statement to solve my problem,as below
Select case when decode(to_char(add_months(sysdate,9),'Q'),
'1','3',
'2','4',
'3','1',
'4','2',
'') < 3 then to_number(to_char(main_rec.termination_date,''YYYY''))+1 else to_number(to_char(main_rec.termination_date,''YYYY''))
P.S The reason for <3 condition check in CASE Statement is, if a sysdate+9months falls in next Financial year , I need to change Year accordingly.
But,this works only in SQL, in Procedures, i cannot do this using CASE Statement
Can anybody give some ideas on how to approach this?. I have to use this in a cursor (not in the body of my procedure, so condition checking like "If then else " after fetching year is not possible)
Any help would be greatly appreciated.
Thanks,
Surendra Tirumala
Database Administrator
Cabinet for Workforce Development
Commonwealth of Kentucky
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