Re: Hash Tables and PL/SQL (Ora 9.2)

From: mkb <mkb125_at_yahoo.com>
Date: Wed, 11 Jun 2003 08:19:08 -0700
Message-ID: <F001.005AF1FF.20030611075950@fatcity.com>

Ok, I found the bug. Just re-read ch 5 page 5-4 Understanding Associative Arrays (Index-By Tables).

The problem was here:

       if rdt_type.exists(c1_rec.rdt)
       then
          null;
       else
          rdt_type(ctr) := c1_rec.rdt;
      end if;

This should have been:

       if rdt_type.exists(c1_rec.rdt)
       then
          null;
       else
          rdt_type(c1_rec.rdt) := c1_rec.rdt;
      end if;

Now my hash works and has unique values.

mohammed
--- mkb <[EMAIL PROTECTED]> wrote:
> I've been trying to create a hash table using PL/SQL
> but I seem to be running into some trouble. Hoping
> someone can point me in the right direction. I've
> been using PL/SQL Users Guide and Reference Ch 5 as
> a
> guide.
>
> I have the following piece of code:
>
> declare
>
> cursor c1_cur is
> select * from load_tab;
>
> type rdt_rec_type is table of varchar2(30) index
> by
> varchar2(30);
> rdt_type rdt_rec_type;
>
> begin
> open c1_cur;
> loop
> fetch c1_cur into c1_rec;
> exit when c1_cur%notfound;
>
> if rdt_type.exists(c1_rec.rdt)
> then
> null;
> else
> rdt_type(ctr) := c1_rec.rdt;
> end if;
>
> end loop;
>
> end;
> /
>
> My goal is to have only those values in the hash
> table
> (rdt values) that are not dups. I was hoping that
> object.exists(value) would work, but apparently I
> seem
> to be getting everything in my hash.
>
> Any ideas how I can code this?
>
> thanks
>
> mohammed
>
>
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Author: mkb
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Received on Wed Jun 11 2003 - 10:19:08 CDT