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Home -> Community -> Mailing Lists -> Oracle-L -> RE: Which process is taking up so much CPU???
Fermin,
The following query might help you ....
set linesize 120
select substr(vs.username,1,10)username,
vs.osuser,
vs.sid,
vs.serial#,
vs.LOGON_TIME,
to_char(vs.logon_time, 'DD-MON-YY HH24:MI:SS') LOGON_TIME,
substr(vs.machine,1,15)machine,
vs.process,
vp.spid,
vs.last_call_et
Regards
Rafiq
Reply-To: ORACLE-L_at_fatcity.com
To: Multiple recipients of list ORACLE-L <ORACLE-L_at_fatcity.com>
Date: Mon, 31 Mar 2003 07:54:03 -0800
Dennis, you seem to be have a master in Oracle! please can you help, I can see the SPID column under table v$process, but how do I link it to table v$session so that I actually know which UNIX process it corresponds to. I think there must be another table that links both of them; you talk about the shadow process, where is it or where can I get more info on it.
Thank you for your time.
Fermin.
-----Mensaje original-----
De: root_at_fatcity.com [mailto:root_at_fatcity.com]En nombre de DENNIS
WILLIAMS
Enviado el: jueves, 27 de marzo de 2003 18:49
Para: Multiple recipients of list ORACLE-L
Asunto: RE: Which process is taking up so much CPU???
Fermin
The spid column in the v$process column matches the Unix process i.d.
You
may need to track it back through the Oracle shadow process.
Dennis Williams
DBA, 40%OCP, 100% DBA
Lifetouch, Inc.
dwilliams_at_lifetouch.com
-----Original Message-----
Sent: Thursday, March 27, 2003 9:14 AM
To: Multiple recipients of list ORACLE-L
I usually track our HP-UX 11.0 system with the 'top' command so I can notice when the system is under slow performance. If that happens, I use Toad to look for any active Oracle SQL query which may be heavy enough for degrading the performance.
I think my question is simple, but since I am a newbie on this... how can I see who is executing an Oracle SQL that is taking all our CPU provided that I only see his PID with the TOP command? I only see the oracle process, but I don't know how to get the username and the SQL beside him.
Thank you for your answers!
Fermin.
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