Re: Select count(name) from table group by name where count(name)

Thanks.

On Thursday 29 August 2002 16:47, you wrote:
> Use HAVING count(name) = 1
>
> Example from our good friend scott.emp
>
> SQL> select job, count(job)
> 2 from emp
> 3 group by job;
>
> JOB COUNT(JOB)
> --------- ----------
> ANALYST 2
> CLERK 4
> MANAGER 3
> PRESIDENT 1
> SALESMAN 4
> 0
>
> 6 rows selected.
>
> SQL> i
> 4 having count(job) = 1
> 5
> SQL> l
> 1 select job, count(job)
> 2 from emp
> 3 group by job
> 4* having count(job) = 1
> SQL> /
>
> JOB COUNT(JOB)
> --------- ----------
> PRESIDENT 1
>
>
> -----Original Message-----
> Sent: Thursday, August 29, 2002 4:39 PM
> To: Multiple recipients of list ORACLE-L
> 1
>
>
> Hello guys,
>
> I am baffled by this problem.
>
> I need to fish out the person's name from a list but I only want the
> name of the person that occurs once in the list - minus those names that
> occurs more than once.
>
> Now, I know about "distinct" and "unique", but this is not what I want.
> All I want is to be able to fish out the names of the people who have
> only one and exactly only one entry in the list. I do not want the names
> of those people who have more than one entry in the list.
>
> Could one of you do me a huge favor give me some hints as to how to
> contruct the select statement for this.
>
> Thanks.
>
> ltiu

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-- 
Author: ltiu
  INET: ltiu_at_alumni.sfu.ca

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