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Home -> Community -> Mailing Lists -> Oracle-L -> RE: OT : kernel using 75% of CPU
<FONT face=Arial color=#0000ff
size=2>Jerry;
Has there been any system parameter changes lately ??
<FONT face=Arial color=#0000ff
size=2>
I
don't know about on your system, but on our AIX box there was a parameter called
MBUFs that dealt with Communication Buffers. Now, you would not think this
would have any consideration on the database, but it did.
<FONT face=Arial color=#0000ff
size=2>
MBUFS
is the Maximum Allowable Communication Buffer on an AIX system. We
thought that it dealt with the networking and set it up to its maximum of 64
Meg. We also did not think this would bother Oracle.... boy were we
wrong.
<FONT face=Arial color=#0000ff
size=2>
<FONT face=Arial color=#0000ff
size=2>Apparently, its also Interprocess comminications as well. And,
since Oracle is greedy, it likes to take all the memory the system will give
it. It turned out that each process that was started (i.e. every user who
logged on ) grabbed the maximum memory setup by MBUFS. So, take a 900 Meg
SGA and add onto it a 1 Meg Sort area per user and a 64 Meg MBUF per user and
350 users and you can see why our 4GB of memory went real
fast.
<FONT face=Arial color=#0000ff
size=2>
<FONT face=Arial color=#0000ff
size=2>Sometimes, things that don't appear to be related can all of a sudden
jump up and bite you.
<FONT face=Arial color=#0000ff
size=2>
<FONT face=Arial color=#0000ff
size=2>Kevin
<FONT face=Tahoma
size=2>-----Original Message-----From: Jerry C
[mailto:usidba_at_yahoo.com]Sent: Tuesday, August 28, 2001 4:46
PMTo: Multiple recipients of list ORACLE-LSubject: Re:
OT : kernel using 75% of CPU
Guy,
Thank you very very much, this is a great
explanation, and is much appreciated.
To answer some of your questions (and add
a few!):
Yes, our client is experiencing
performance problems.
vmstat and swap -s seem to show some
swapping:
csuaor46> vmstat 2
10 procs memory page disk faults cpu r b w swap free re mf pi po fr de sr s6 s1 s1 s5 insy cs us sy id 2 0 0 14536 14776 67 1514 15 228 957 62760 262 0 2 2 0 640 115 931 25 25 50 2 0 0 6179304 62416 36 1893 0 744 5500 56488 1126 0 4 4 0 988 6159 917 23 55 22 1 0 0 6177696 62600 20 908 0 1032 11808 56488 2488 0 6 6 0 917 3781 667 24 51 25 0 0 0 6181688 62960 89 1528 4 288 444 56488 37 0 6 6 0 1076 19029 862 23 54 23 1 0 0 6181336 64432 15 1269 0 140 576 56488 110 0 1 1 0 456 8550 493 14 46 40 0 0 0 6182376 63776 18 2976 4 368 1008 62760 328 0 8 8 0 594 6163 831 14 54 32 2 0 0 6180800 63072 9 1746 0 300 1296 62760 202 0 1 1 0 661 4441 693 12 65 23 0 0 0 6178120 62728 47 1311 4 612 2272 56488 464 0 3 2 0 829 5535 801 34 38 28 2 0 0 6179944 64616 36 1322 0 364 764 62760 70 0 0 0 0 996 4786 739 13 69 18 0 0 0 6183112 62560 40 856 4 340 1444 62760 339 0 1 2 0 822 4107 707 10 40 50csuaor46> swap -stotal: 2602216k bytes allocated + 19960k reserved = 2622176k used, 6177752k available I would assume swapping operations would be included under "kernel"? The app also uses java, is there any way to determine if Java is performing any wacky system calls?
Sent: Tuesday, August 28, 2001 1:45
PM
Subject: RE: OT : kernel using 75% of
CPU
<SPAN
class=315352916-28082001>Hi Jerry,
<SPAN
class=315352916-28082001>
<SPAN
class=315352916-28082001>Firstly, the kernel is not a process in the
conventional sense. It is basically a set of library functions. One of these
is the scheduler, which gets called every time slice, by the timer in the
hardware, in order to decide which actual process to run next. Responding to
interrupts is the only way in which a kernel could be considered to be
running. The kernel exists to provide services to processes, every time a
process makes a "system call", for example to perform I/O, this is invoking
a function within the kernel to actually "do" it - i.e. an application might
call read() then read() in the kernel would handle the business of talking
to the device driver and actually doing the reading of the data from the
disk (for example).
<SPAN
class=315352916-28082001>
<SPAN
class=315352916-28082001>The CPU states line is showing you *where* the code
is running. If it's in "user" then the CPU is spending its time running code
in "user land" - probably computational code, stuff that's actually in the
application. If the state is "kernel", then it means that your application
is making lots of system calls, and the kernel level routines are doing the
work.
<SPAN
class=315352916-28082001>
<SPAN
class=315352916-28082001>Incidentally, this is why Java is a good language
on the server - it does much of its real work in fast kernel space, and
little of it in the slow virtual machine. A busy Oracle will also spend a
bit of time in kernel space, doing I/O and networking, accessing shared
memory, etc.
<SPAN
class=315352916-28082001>
<SPAN
class=315352916-28082001>Looking at your "top" output, you have a high
system load, but your user processes aren't using much CPU, but kernel time
is high. This suggests that your processes are spending time waiting for the
kernel to do something or other for them, load being the size of the run
queue (all the processes that are ready to run but not actually on the CPU).
Are you actually experiencing performance problems? If so, you need to look
at what the system is doing using "sar" "vmstat" and "iostat". One thing to
watch out for is that "top" is a primitive tool. Notice how large all your
Oracle processes are? That is because top isn't smart enough to realize that
they're all connected to shared memory, it's counting each one as being
process size + SGA. So your processes and your memory in use don't add up.
Also top deals poorly with LWPs (threads) - are you using MTS? You could
simply be seeing threads stacking up as they wait for
network.
<SPAN
class=315352916-28082001>
<SPAN
class=315352916-28082001>HTH,
<SPAN
class=315352916-28082001>
<SPAN
class=315352916-28082001>g
<SPAN
class=315352916-28082001>
<FONT face=Tahoma size=2>-----Original Message-----From: Jerry C [mailto:usidba_at_YAHOO.COM]Sent: Tuesday, August 28, 2001 4:20 PMTo: Multiple recipients of list ORACLE-LSubject: OT : kernel using 75% of CPU Hi there, I have a Sun e4500, running Solaris 2.7 and Oracle 8.1.7.1.0. Everything looks normal from a database perspective, but when I run "top" it show the kernel being very hog-like: load averages: 14.38, 15.18, 15.18 07:16:21126 processes: 118 sleeping, 4 running, 4 on cpuCPU states: 0.6% idle, 26.6% user, 72.8% kernel, 0.0% iowait, 0.0% swapMemory: 4096M real, 63M free, 216M swap in use, 5310M swap free PID USERNAME THR PRI NICE SIZE RES STATE TIME CPU COMMAND 2286 oracle 1 0 0 1844M 1814M run 9:44 13.90% oracle11068 oracle 1 0 0 2056K 1536K cpu0 0:02 1.53% top11333 oracle 1 0 0 1150M 1124M cpu1 0:01 1.39% oracle 5944 oracle 1 40 0 1820M 1789M sleep 14:40 1.36% oracle 4797 root 1 50 0 2112K 1248K sleep 6:01 1.36% top11346 oracle 1 0 0 110M 92M cpu0 0:01 1.26% oracle11114 oracle 1 0 0 1009M 984M cpu1 0:00 0.66% oracle11157 oracle 1 0 0 1009M 984M run 0:00 0.63% oracle11368 oracle 1 33 0 1794M 1765M sleep 0:00 0.29% oracle19558 oracle 1 60 0 1797M 1751M sleep 78:28 0.28% oracle19554 oracle 1 60 0 1794M 1751M sleep 38:05 0.20% oracle11366 oracle 1 55 0 1793M 1763M sleep 0:00 0.19% oracle11292 oracle 1 26 2 2008K 1424K run 0:00 0.19% dsql Any ideas on what I, as a lowly DBA, would be able to check? It's a bit out of my area and I'm stumped... Thanks! <FONT face="Courier New"
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