Re: Date / Time

Sajid,

    Unfortunately, I ran into the same problem. I didn't find anything to do it for me, either, so I had to write the pl/sql code. It is very long and messy, but can be done. When I did it, I didn't even attempt the days notation. Here is the code that I wrote:

                    date_diff := trans_cur.modified_date - last_date;
                    date_diff_tot := trans_cur.modified_date - first_date;
                    SELECT decode( trunc( date_diff * 24),0,
                      to_char( trunc( date_diff * 1440), 'FM90') || ':' ||
                      to_char( round( date_diff * 86400) - trunc( date_diff
                        * 1440) * 60,'FM00'),
                      to_char( trunc( date_diff * 24),'FM90') || ':' ||
                      to_char( trunc( date_diff * 1440 - trunc( date_diff *
24)
                        * 60),'FM00') || ':' ||
                      to_char( round( date_diff * 86400 - trunc( date_diff
                        * 1440) * 60), 'FM00')),
                      decode( trunc( date_diff_tot * 24), 0,
                      to_char( trunc( date_diff_tot * 1440),'FM90') || ':' ||

                      to_char( round( date_diff_tot * 86400)
                        - trunc( date_diff_tot * 1440) * 60,'FM00'),
                      to_char( trunc( date_diff_tot * 24),'FM90') || ':' ||
                      to_char( trunc( date_diff_tot * 1440
                        - trunc( date_diff_tot * 24) * 60),'FM00') || ':' ||
                      to_char( round( date_diff_tot * 86400
                        - trunc( date_diff_tot * 1440) * 60), 'FM00'))
                    INTO elapsed_1, elapsed_2
                    FROM dual;

I hope this helps.

Sajid Iqbal wrote:

> Hello All
>
> I want to display the "time elapsed" between two dates - in days, hours,
> minutes and seconds.
>
> If I do "select date1 - date2", the result is : 12.0194907
>
> Is there a function that will turn the number of days into something more
> legible? Ideally i'd like to do ;
>
> "to_char(12.0194907,'DD:HH:MI:SS')" but obviously that won't work. Is
> there a solution other than writing a complex function myself which will
> have to * by 24, / by 60 and substr etc to get the different bits of the
> number?
>
> Please CC any replies directly to me at siqbal_at_vianetworks.co.uk
>
> Thanks in advance,
> Saj.
>
> --
> Sajid Iqbal
> Database Team Leader
>
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--
Scott Canaan (srcdco_at_rit.edu)
(716) 475-7886
"Life is like a sewer, what you get out of it depends on what you put into
it" - Tom Lehrer


-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.com
-- 
Author: Scott Canaan
  INET: srcdco_at_ritvax.isc.rit.edu

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