RE: SQL Question

From: Vadim Gorbounov <vgorbounov_at_simplyengineering.com>
Date: Wed, 24 Jan 2001 12:22:04 -0500
Message-Id: <10751.127380@fatcity.com>

	Hi, Lee,
	Will this do right job for you?

select distinct HOUSE_KEY, SOURCE_CODE, DATE_OBTAINED, THIRD_PARTY from A) a, b where a.cust_key=b.cust_key
and exists (select null from a c where a.SOURCE_CODE =c.SOURCE_CODE and a.DATE_OBTAINED = c.DATE_OBTAINED and

   a.THIRD_PARTY = c.THIRD_PARTY and a.cust_key <> c.cust_key);         

	Vadim Gorbounov
	Oracle DBA

-----Original Message-----
From: lerobe - Lee Robertson [mailto:LEROBE_at_acxiom.co.uk] Sent: Wednesday, January 24, 2001 9:11 AM To: Multiple recipients of list ORACLE-L Subject: SQL Question

All,  

As you have probably guessed by now, my SQL isn't the srongest so I would appreciate some help if you could.  

Two tables  

Table A

---

CUST_KEY
SOURCE_CODE
DATE_OBTAINED
THIRD_PARTY
plus other columns  

Table B

---

CUST_KEY
HOUSE_KEY
other columns.  

What I need to do is find all rows in Table A where columns 2,3 and 4 have the same value (col 1 can be different) and then link to table B and join with cust key to find out which rows have distinct house_keys.  

Data Example  

Table A  

Col1       Col2       Col3       Col4
1            3            3            4
2            3            2            4
3            3            2            4
4            4            4            4
5            5            4            3
6            5            4            3                          in this

example I would only require rows 2 and 3, and 5 and 6.  

Any ideas (other than me going on an SQL writing course !!!).  

Regards  

Lee Robertson
Acxiom
Tel: 0191 525 7344
Fax: 0191 525 7007
Email: lerobe_at_acxiom.co.uk  

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Author: lerobe - Lee Robertson
  INET: LEROBE_at_acxiom.co.uk

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