RE: time interval

Hi,
I'm not sure if this is the best way, but it works, the 1440 is the number of minutes in a day (24 * 60)

SQL> r
  1 select 1440 * (
  2 to_date('12-APR-99 12:00:00','DD-MON-YY HH24:MI:SS')   3 - to_date('11-APR-99 13:00:00','DD-MON-YY HH24:MI:SS')   4 ) Difference
  5* from dual

DIFFERENCE

      1380

/Debbie

-----Original Message-----
From: root_at_fatcity.com [mailto:root_at_fatcity.com]On Behalf Of Xin "Michael" Wu
Sent: Tuesday, August 22, 2000 7:52 PM
To: Multiple recipients of list ORACLE-L Subject: time interval

Hi, All:

Is there any way to track the difference of time components (in minutes) between two dates?

Thanks,

Mike

--
Author: Xin \"Michael\" Wu
  INET: xwu_at_sempratrading.com

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