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DISTINCT in XMLQuery ?? [message #278604]

Mon, 05 November 2007 02:38

panzertape
Messages: 20
Registered: August 2007

Junior Member

Hi !
I have a problem with duplicate values. So I thought I could get rid of them by using DISTINCT. But I don't know where to place it Sad

Thats my Statement:

select XMLElement
("Table1",
XMLElement
("Table1_ITEM", XMLForest(--elements--) )
,
XMLElement
("Table2",
XMLAgg ( XMLElement
( "Table2_ITEM", XMLForest(--elements--) )
)
,
XMLElement
("Table3",
XMLAgg
(XMLElement
("Table3_ITEM", XMLForest(--elements--) )
)
)
))).getClobVal() AS XML

FROM Table1, Table2, Table3
WHERE Table1.ID = Table2.ID AND Table2.ID = Table3.ID
AND Table1.ID = 9439

GROUP BY --table1 elements--

The Statement works fine but I'm getting duplicate values Sad

So do you have any ideas that could help to solve my problem??
Any help would be appreciated

thanks
panzertape

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Re: DISTINCT in XMLQuery ?? [message #278605 is a reply to message #278604]

Mon, 05 November 2007 02:40

Littlefoot
Messages: 21823
Registered: June 2005
Location: Croatia, Europe

Senior Member
Account Moderator

I don't know XML, but DISTINCT (in pure SQL statement) must follow the SELECT keyword. So, it would be

SELECT DISTINCT ...

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Re: DISTINCT in XMLQuery ?? [message #278609 is a reply to message #278604]

Mon, 05 November 2007 02:45

panzertape
Messages: 20
Registered: August 2007

Junior Member

When I do it this way (just SELECT DISTINCT XMLElement.......), then I'm getting an
ORA-22950: cannot ORDER objects without MAP or ORDER method-error.
Do you know how I can solve this error?

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Re: DISTINCT in XMLQuery ?? [message #278620 is a reply to message #278609]

Mon, 05 November 2007 03:11

Littlefoot
Messages: 21823
Registered: June 2005
Location: Croatia, Europe

Senior Member
Account Moderator

Oracle says

Quote:

ORA-22950: cannot ORDER objects without MAP or ORDER method

Cause: an object type must have a MAP or ORDER method defined for all comparisons other than equality and inequality comparisons.

Action: Define a MAP or ORDER method for the object type

Unfortunately, I wouldn't know what it really means.

This is a completely blind shot: what happens if you add ORDER BY clause at the end of the statement? Something like

SELECT DISTINCT ...
FROM ...
GROUP BY table elements
ORDER BY table_elements

I believe I should give up as I'm probably talking nonsense here.

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Re: DISTINCT in XMLQuery ?? [message #278629 is a reply to message #278604]

Mon, 05 November 2007 03:35

panzertape
Messages: 20
Registered: August 2007

Junior Member

Thanks for trying to help me.
I did it that way (group by ... order by)
But it is still giving me the
ORA-22950: cannot ORDER objects without MAP or ORDER method-error.
any other ideas? Confused

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Re: DISTINCT in XMLQuery ?? [message #278745 is a reply to message #278604]

Mon, 05 November 2007 09:29

panzertape
Messages: 20
Registered: August 2007

Junior Member

i tried it with an Inline View....but that didn't work...
I got still the duplicate values Sad

  FROM table1,
  (select distinct * from table2) ab, 
 (select distinct * from table3) a
  WHERE table1.ID = 9439 
  AND table1.ID = ab.ID 
  AND ab.ID = a.ID

What am I doing wrong??

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Re: DISTINCT in XMLQuery ?? [message #290830 is a reply to message #278745]

Tue, 01 January 2008 04:57

hrishy
Messages: 25
Registered: August 2005

Junior Member

Hi

How about

 FROM table1,
  (SELECT id,sum(columns) * from table2
   GROUP BY id) ab, 
 (select id,sum(columns) from table3
   GROUP BY id) a
  WHERE table1.ID = 9439 
  AND table1.ID = ab.ID 
  AND table1.ID = a.ID

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