Home » RDBMS Server » Server Administration » Can anyone help me answer following question, please?
- Can anyone help me answer following question, please? [message #56793] Fri, 25 April 2003 04:08 Go to next message
Brian
Messages: 38
Registered: October 1999
Member
Hi,
I have some question that cannot find out the answer, please.
Can you help me? If yes, see the following:

- Define relational database

- Default data format

- Difference between DEFINE and ACCEPT

- Command to display table structure

- Difference between CHAR and VARCHAR

- Components of substitution variable

- Write SQL statement

- List mathematical operators in SQL

- Describe SET variable COLSEP

- Describle BREAK command

- How subquery execute

- Usage of ACCEPT

- Write SQL SELECT statement

- Describe two type of subqueries

- Write statement with IN operator

Report message to a moderator

- Re: Can anyone help me answer following question, please? [message #56798 is a reply to message #56793] Fri, 25 April 2003 08:14 Go to previous messageGo to next message
Anand
Messages: 161
Registered: August 1999
Senior Member
I think you need buy a good book on Oracle or check out websites like :

asktom.oracle.com
metalink.oracle.com
orafaq.com

Books are the first choice.

Report message to a moderator

- Re: Can anyone help me answer following question, please? [message #56806 is a reply to message #56793] Sat, 26 April 2003 01:48 Go to previous message
shashi
Messages: 34
Registered: March 2001
Member
Dear friend all the questions are easy and you can get it in oracle documenation(u tyope this in google),i could have answered for your questions but i myself is in trouble , u will get answer for all the questions then also if u dont getmail me if my prob is solved i will help u

Report message to a moderator

Previous Topic: its very urgent pls help me!
Next Topic: how to find the user name who executes sql statement
Goto Forum:
  

[ Syndicate this forum (XML) ] [ RSS ]

Current Time: Mon Apr 14 05:06:35 CDT 2025
.:: Forum Home :: Blogger Home :: Wiki Home :: Contact :: Privacy ::.