| Long data type Urgent [message #373331] |
Wed, 11 April 2001 13:32  |
aish74
Messages: 19
Registered: March 2001
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Junior Member |
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Hi ,
I am trying to do this
SELECT * FROM table WHERE seqno > value
(seqno is a long data type)
I am getting error "Illegal use of long data type.
Could anybody tell me how do I put the condition?
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| Re: Long data type Urgent [message #373334 is a reply to message #373333] |
Wed, 11 April 2001 14:51  |
aish74
Messages: 19
Registered: March 2001
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Junior Member |
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Then I want to change the datatype from long to no is it possible.
I tried creating another table and copying the data but was unable to do so bcos of the long datatype in the old table.
Please anybody let me know
1.How do I change the datatype long to number.
2.or copy the long datatype in to a number column
or insert londata type column in to another table
of number datatype column?
Please help
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| Re: Long data type Urgent [message #373335 is a reply to message #373333] |
Wed, 11 April 2001 15:12 |
Andrew again...
Messages: 270
Registered: July 2000
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Senior Member |
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CREATE TABLE new_tab(col1 date, col2 VARCHAR2(4000));
LOCK TABLE old_tab IN EXCLUSIVE MODE NOWAIT;
DECLARE
CURSOR datacursor IS SELECT col1, col2 FROM old_tab;
datarecord datacursor%ROWTYPE;
BEGIN
OPEN datacursor;
LOOP
FETCH datacursor INTO datarecord;
EXIT WHEN (datacursor%NOTFOUND);
INSERT INTO new_tab(col1, col2) VALUES (datarecord.col1, datarecord.col2);
END LOOP;
END;
/
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| Re: Long data type Urgent [message #373337 is a reply to message #373333] |
Wed, 11 April 2001 15:42 |
aish
Messages: 44
Registered: March 2001
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Member |
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Hi Andrew ,
I tried your SQl but I got error like
" expression is of wrong type"
please let me know what do I do next.
Note :I tried your statement without col(long datatype) and it worked.
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| Re: Long data type Urgent [message #373338 is a reply to message #373333] |
Wed, 11 April 2001 15:42 |
aish
Messages: 44
Registered: March 2001
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Member |
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Hi Andrew ,
I tried your SQl but I got error like
" expression is of wrong type"
please let me know what do I do next.
Note :I tried your statement without col(long datatype) and it worked.
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| Re: Long data type Urgent [message #373340 is a reply to message #373333] |
Wed, 11 April 2001 16:02 |
Andrew again...
Messages: 270
Registered: July 2000
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Senior Member |
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it works for me from sql*plus on 8i...
CREATE TABLE old_tab(col1 date, col2 long);
-- 5000 long!
insert into old_tab values (sysdate, lpad('a', 5000, 'b'));
insert into old_tab values (sysdate, lpad('x', 5000, 'y'));
CREATE TABLE new_tab(col1 date, col2 VARCHAR2(4000));
LOCK TABLE old_tab IN EXCLUSIVE MODE NOWAIT;
DECLARE
CURSOR datacursor IS SELECT col1, col2 FROM old_tab;
datarecord datacursor%ROWTYPE;
BEGIN
OPEN datacursor;
LOOP
FETCH datacursor INTO datarecord;
EXIT WHEN (datacursor%NOTFOUND);
INSERT INTO new_tab(col1, col2) VALUES (datarecord.col1, datarecord.col2);
END LOOP;
END;
-- Trimmed to length 4000!
select length(col2) from new_tab;
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