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"John Russell" <netnews6_at_johnrussell.mailshell.com> wrote in message news:lfq3jvoludjfv4bvkoa3po9oq7j07kicn9_at_4ax.com...
>
Heh! If you use Pi=3.141592653589,
that will give you enough precision to calculate
the perimeter of the Moon orbit with less than
a millimeter error. Just in case you need too much
precision...
<g,d&r>
-- Cheers Nuno Souto wizofoz2k_at_yahoo.com.au.nospamReceived on Thu Aug 07 2003 - 06:29:52 CDT