RE: OT-is there a way to do this in unix - date question

You pretty much had it.

Linux
#!bin/sh

echo `date --date=3D$1/12/2005 +%b`

Other Unix OS's
#!bin/sh

echo `date -d=3D$1/12/2005 +%b`

Your script could just ececute this script, however it is probably just = as easy to make it a function call within the shell script itself that = needs this information or a direct variable call to the date funtion = using the original passed variabl or internal variable from your = program.

-----Original Message-----
From: oracle-l-bounce_at_freelists.org =
[mailto:oracle-l-bounce_at_freelists.org] On Behalf Of Mark W. Farnham Sent: Friday, February 11, 2005 2:28 PM
To: Oracle-L
Subject: RE: OT-is there a way to do this in unix - date question

#! /bin/sh
# Copyleft (C) 2005 Rightsizing, Inc.
#
# mm2mon -- wrapper for date to return 3 char month abbrev from numeric =
arg
# with not even a hint of error checking.
#
# Usage: mm2mon <arg>
#

datedummy=3D`printf 2005%02d01 $1`
/usr/bin/date -d$datedummy +%b

This seems to work. The returns change based on your local language, = though.
If you have a version of the date command that does not take the -d = argument this will laugh at you, otherwise it should work fine.

A real shell person may know a cheaper way to format the string than = invoking printf; that part of my brain is off on tape somewhere. I think = you have to give the -d option a formatted string and it will figure out = yymmdd and yyyymmdd. In your case any old yyyy and dd will do.

If you want "like what you get with date +%b" then this is actually what = you want.

>
> <ganstadba_at_hotmail.com> wrote:
> > without writing a whole series of ifs, given a number 1 - 12 give=20
> > the corresponding three letter month like what you get with date=20
> > +%b, but someone supplies you the digits
> > --
> > http://www.freelists.org/webpage/oracle-l

--
Peter Johnson
Humboldt State University
707-826-6122

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