RE: How can I get the DD,MM, YYYY part of the every day in a duration of 10 years

Thanks Stephane / Zorac

I am able to run the query, and can retrieve the individual component of the date: SELECT rownum ,to_char( ret_date,'DD') day,to_char( ret_date,'MM') month,to_char( ret_date,'YYYY') year, ret_date FROM (select (to_date('31/12/1998','DD MM YYYY') + rownum) ret_date from dba_objects,dba_objects where rownum < (TO_DATE('01/01/2010','DD/MM/YYYY') - TO_DATE('01/01/1999','DD/MM/YYYY')) )

|Thanks all

Regards

Sanjay

From: Stephane Faroult [mailto:sfaroult_at_roughsea.com] Sent: Tue 2/1/2005 5:17 PM
To: oracle-l_at_freelists.org; Sanjay Khangarot (WT01 - MANUFACTURING) Subject: Re: How can I get the DD,MM, YYYY part of the every day in a duration of 10 years

10 years = about 3600 rows

I suppose that T is a 4000+ row table

select to_char(to_date('01/01/1999', 'DD/MM/YYYY') + rownum - 1, 'MM DD YYYY') from T
where rownum < to_date('01/01/2010', 'DD/MM/YYYY') - to_date('01/01/1999', 'DD/MM/YYYY')

Regards,

Stephane Faroult

RoughSea Ltd

http://www.roughsea.com

On Tue, 1 Feb 2005 16:01 , <sanjay.khangarot_at_wipro.com> sent:

	Hi,
	I want to generate one script which can return me dd,mm , yyyy part of every day for a duration, for example ..
	if I start from Jan 01,1999 to jan 01, 2010 then wanted the record for every day..
	01 01 1999
	02 01 1999
	....

	till
	01 01 2010..

	this will be used to create one time dimension..

	TIA

	Regards

	Sanjay





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