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Hello,
=20
I already made it. Like this:
=20
select to_date(:starting_date_minus_one,'DD MM YYYY') + rownum
from xxx
where rownum <=3D :number_of_days
=20
=20
Thanks,
Trindade
-----Mensagem original-----=20 De: oracle-l-bounce_at_freelists.org em nome de ajvctrindade=20 Enviada: ter 01-02-2005 12:00=20 Para: zoran_martic_at_yahoo.com; sanjay.khangarot_at_wipro.com; = oracle-l_at_freelists.org=20 Cc:=20 Assunto: RE: How can I get the DD,MM, YYYY part of the every day in a =duration of 10 years
Hello, =3D20 I did try that with no sucess. =3D20 Can you explain me better please? =3D20 Thanks, Ant=3DF3nio Trindade =09 -----Mensagem original-----=3D20 De: oracle-l-bounce_at_freelists.org em nome de Martic Zoran=3D20 Enviada: ter 01-02-2005 10:45=3D20 Para: sanjay.khangarot_at_wipro.com; oracle-l_at_freelists.org=3D20 Cc:=3D20 Assunto: Re: How can I get the DD,MM, YYYY part of the every = day in a =3D duration of 10 years =3D09 =3D09 =09 Hi Sanjay, =3D09 Something like this should do it for you =3D09 select to_date(:1,'DD MM YYYY') + rownum from xxx,xxx where rownum < (:2 - :1) =3D09 You need to replace :1 and :2 as binds for your dates. =3D09 Will cover up to 1M days. xxx is just a table with 1000 rows from 1 to 1000. =3D09 Regards, Zoran =3D09 --- sanjay.khangarot_at_wipro.com wrote: =3D09=09
> Hi,
> I want to generate one script which can return me
> dd,mm , yyyy part of every day for a duration, for
> example ..
> if I start from Jan 01,1999 to jan 01, 2010 then
> wanted the record for every day..
> 01 01 1999
> 02 01 1999
> ....
>
> till
> 01 01 2010..
>
> this will be used to create one time dimension..
>
> TIA
>
> Regards
>
> Sanjay
>
>
>
>
>
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-- http://www.freelists.org/webpage/oracle-lReceived on Tue Feb 01 2005 - 07:19:45 CST