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RE: OffTopic : sed : Alternate (2,4,6..) replacement

From: <Stephen.Lee_at_DTAG.Com>
Date: Tue, 16 Dec 2003 08:04:31 -0800
Message-ID: <F001.005DA17C.20031216080431@fatcity.com>

Will this work?



#!/usr/bin/ksh
THINGY=0
cat swt | sed 's/:/ /' | while read A B JUNK; do

   if [ $THINGY -eq 1 ]; then

      B="that"
      THINGY=0
   else
      THINGY=1

   fi
   echo "$A:$B $JUNK"

done


You can set up a similar loop in awk too. The sed 's/:/ /' changes the colon to a space so that the read A B JUNK will work.

> -----Original Message-----
>
> Hi List
> I need some help on this;
> How do i replace the 2nd,4th,6th occurances of a column
> (vertical) in a
> file.
> I know sed does it within a row
>
> $ cat swt
> 01:this is a file1 this
> 02:this is a file1 this
> 03:this is line3
> 04:this is line4
>
> $ sed 's/this/that/2' swt
> 01:this is a file1 that
> 02:this is a file1 that
> 03:this is line3
> 04:this is line4
> $ sed 's/this/that/1' swt
> 01:that is a file1 this
> 02:that is a file1 this
> 03:that is line3
> 04:that is line4
>
> But i want
> 01:this is a file1 this
> 02:that is a file1 this
> 03:this is line3
> 04:that is line4
>
> I tried awk but awk seems to be going one line at a time.
>
> Thanks in Advance.
>
> GovindanK
>
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> Author: GovindanK
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>
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-- 
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-- 
Author: <Stephen.Lee_at_DTAG.Com
  INET: Stephen.Lee_at_DTAG.Com

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Received on Tue Dec 16 2003 - 10:04:31 CST

Original text of this message

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