RE: SQL question

From: Fink, Dan <Dan.Fink_at_mdx.com>
Date: Mon, 23 Sep 2002 09:28:26 -0800
Message-ID: <F001.004D6BEE.20020923092826@fatcity.com>

It is a little awkward, but a union in an inline query may do the trick:

1 select a.code

  2  from (select '10' code from dual union
  3        select '20' code from dual union
  4        select '30' code from dual union
  5        select '40' code from dual union
  6        select '50' code from dual ) a

7* where a.code not in (select to_char(deptno) from emp) SQL> / CO
--

40
50

Dan Fink

-----Original Message-----

Sent: Monday, September 23, 2002 10:28 AM To: Multiple recipients of list ORACLE-L

Good morning list,

Environment HP-UX 11.0 Oracle 8.1.6

Can anyone help with this SQL.

I can get a result set of values from a table that match a given list of values -

select code
from table
where code in ('A','B','C','D','E')

I can get a result set of values from a table that do not match a given list of values -

select code
from table
where code not in ('A','B','C','D','E')

So far so good.

Now, how do I get the set of values from the list that do NOT have a matching value in the table?

I cannot create any objects in the schema I am working in otherwise I would create a table with the values and do a minus, but I can't figure out how to do it in SQL only.

Thanks in advance, folks.

Steve
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--

Author: Steven Haas
INET: steven.haas_at_snet.net

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Author: Fink, Dan
INET: Dan.Fink_at_mdx.com

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