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Output in 1 line in the spool file from a sql statement - please help

From: Viraj Luthra <viraj999_at_lycos.com>
Date: Tue, 13 Feb 2001 21:49:25 -0800
Message-ID: <F001.002B35EC.20010213214526@fatcity.com>

Hello,

I need some help. I need all the columns values on 1 line only. that is in the end of this mail you will see the result as,


V$ACCESS                                 
SYNONYM                  8               
PUBLIC                                   

--------------------------------------------------------------
I need the above as
V$Access                  Synonym          8         public 

all with the correct width as defined in the sql statement. Have you any clue as to what to do?

I have tried different linesizes... also but no use Regards,

Raja                                        
                                         

--------------------------------------------------

This is the script that I run:-

run_sql()                                                    
{                                                            
sqlplus -s system/manager_at_orcl815 <<!                        
set linesize 78  (also tried linesize 1000 but no use)
col a format a254                                            
col b format a24                                             
col c format 9999999                                         
col d format a64                                             
set echo off feedback off  head off                          
spool 4.lst                                                  
select  substr(object,1,254) a,                              
        substr(type,1,24) b,                                 
        substr(sid,1,7) c,                                   
        substr(owner,1,64) d                                 
from v\$access                                               
order by owner                                               
/                                                            
spool off                                                    
!                                                            
cat 4.lst |sed 's/   *$//' > 5.lst                           
}                                                            
                                                             
run_sql                                                      


+++++++++++++++++++++++++++++++++++++++++++++++++++

The output I get is like this:-

V$ACCESS                                 
SYNONYM                  8               
PUBLIC                                   
                                         
DBMS_APPLICATION_INFO                    
PACKAGE                  8               
SYS                                      
                                         



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Author: Viraj Luthra
  INET: viraj999_at_lycos.com

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Received on Tue Feb 13 2001 - 23:49:25 CST

Original text of this message

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