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XML parsing..plz help [message #178409]

Wed, 21 June 2006 01:38

bhagat.singh-j
Messages: 39
Registered: April 2006

Member

Hi,
Can someone help out in parsing the XML below to get the value of uid?
I need to get the value 'bc4184'?

<?xml version="1.0" encoding="UTF-8" ?>
- <GDSDataServlet>
- <request>
<filter>(extshortname=devendran.a)</filter>
<attributes>dn</attributes>
<context />
<scope>subtree</scope>
</request>
- <results>
- <node name="o=world">
- <node name="ou=mnc">
- <node name="ou=people">
<node name="uid=bc4184" />
</node>
</node>
</node>
</results>
</GDSDataServlet>

Thank you!
Bhagat

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Re: XML parsing..plz help [message #180444 is a reply to message #178409]

Mon, 03 July 2006 09:22

JRowbottom
Messages: 5933
Registered: June 2006
Location: Sunny North Yorkshire, ho...

Senior Member

The answer is 'Not Easily' (a you may have guesed by the lack of replies.

I've got a solution, but it relies upon the Node element that has the "name" attribute you are looking for being the lowest element with the name "Node", and that this situation marks the node you are looking for.

SQL> set serveroutput on size 10000
SQL> declare
  2    v_xml     xmltype;
  3    v_extract xmltype;
  4  begin
  5  
  6  v_xml := xmltype('<GDSDataServlet>
  7  <request>
  8  <filter>(extshortname=devendran.a)</filter> 
  9  <attributes>dn</attributes> 
 10  <context /> 
 11  <scope>subtree</scope> 
 12  </request>
 13  <results>
 14  <node name="o=world">
 15  <node name="ou=mnc">
 16  <node name="ou=people">
 17  <node name="uid=bc4184" /> 
 18  </node>
 19  </node>
 20  </node>
 21  </results>
 22  </GDSDataServlet>');
 23  
 24  v_xml := xmltype.extract(v_xml,'//node[count(node)=0]/@name');
 25  
 26  dbms_output.put_line(substr(xmltype.getstringval(v_xml),1,255));
 27  end;
 28  /
uid=bc4184

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Re: XML parsing..plz help [message #180445 is a reply to message #180444]

Mon, 03 July 2006 09:26

JRowbottom
Messages: 5933
Registered: June 2006
Location: Sunny North Yorkshire, ho...

Senior Member

I spoke too soon. It turns out I can use the "contains" function in a way I hadn't thought of.

This will return you the value of the Name attribute for al elements called "node" which have an attribute called "name" with a value starting with "uid"

SQL> declare
  2    v_xml     xmltype;
  3    v_extract xmltype;
  4  
  5  begin
  6  
  7  v_xml := xmltype('<GDSDataServlet>
  8  <request>
  9  <filter>(extshortname=devendran.a)</filter> 
 10  <attributes>dn</attributes> 
 11  <context /> 
 12  <scope>subtree</scope> 
 13  </request>
 14  <results>
 15  <node name="o=world">
 16  <node name="ou=mnc">
 17  <node name="ou=people">
 18  <node name="uid=bc4184" /> 
 19  </node>
 20  </node>
 21  </node>
 22  </results>
 23  </GDSDataServlet>');
 24  
 25  v_xml := xmltype.extract(v_xml,'//node[starts-with(@name,"uid")]/@name');
 26  
 27  dbms_output.put_line(substr(xmltype.getstringval(v_xml),1,255));
 28  end;
 29  /
uid=bc4184

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