OraFAQ Forum: Unix » Date format in Korn Shell script

Home » Infrastructure » Unix » Date format in Korn Shell script

Show: Today's Messages :: Polls :: Message Navigator
E-mail to friend

Date format in Korn Shell script [message #98477]

Thu, 18 November 2004 11:48

Pinki
Messages: 5
Registered: September 2004

Junior Member

I have a date varible var. I am stripping the value of var to get each of these values to out1.txt, out2.txt and out3.txt. Now I have 2004 17 and 11 in 0ut3.txt, out2.txt and out1.txt.
I would like to print the dateout variable in the format "2004-11-17" and also store this value in this format.

Filename: test1.sh

var=11/17/2004
echo ${var} | cut -c1-2>out1.txt
echo ${var} | cut -c4-5>out2.txt
echo ${var} | cut -c7-10>out3.txt

Any suggestions?

Report message to a moderator

Re: Date format in Korn Shell script [message #98478 is a reply to message #98477]

Thu, 18 November 2004 17:40

Jai Vrat Singh
Messages: 205
Registered: September 2002
Location: Singapore

Senior Member

From UNIX Man Page:

     mm    Month number

     dd    Day number in the month

     HH    Hour number (24 hour system)

     MM    Minute number

     SS    Second number

     cc    Century minus one

     yy    Last 2 digits of the year number

You can use this to get the date required in the correct format itself as

[jsingh@dv_css5b]:/home/jsingh % date "+%Y-%m-%d"
2004-11-19

But if you want it to be extracted from variable itself then use this

#!/bin/ksh

var=11/17/2004

echo $var| awk -F'/' '{ printf ("%s-%s-%s",$3,$1,$2); }'

Report message to a moderator

Previous Topic:	Oracle Integration with Microsoft Active Directory on Unix Platform
Next Topic:	script to log into all oracle databases in one unix server

Goto Forum:

-=] Back to Top [=-

[ Syndicate this forum (XML) ] [

]

Current Time: Tue Oct 28 08:21:07 CDT 2025